# Find Minimum in Rotated Sorted Array II

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.

(i.e., `[0,1,2,4,5,6,7]` might become `[4,5,6,7,0,1,2]`).

Find the minimum element.

The array may contain duplicates.

**Example 1:**

```
Input:
 [1,3,5]

Output:
 1
```

**Example 2:**

```
Input:
 [2,2,2,0,1]

Output:
 0
```

**Note:**

* This is a follow up problem to [Find Minimum in Rotated Sorted Array](https://leetcode.com/problems/find-minimum-in-rotated-sorted-array/description/).
* Would allow duplicates affect the run-time complexity? How and why?

## Analysis

作为[Find Minimum in Rotated Sorted Array](https://leetcode.com/problems/find-minimum-in-rotated-sorted-array/description/) 的follow-up，差别在于是否有重复。跟[Search in Rotated Sorted Array II](find-minimum-in-rotated-sorted-array-ii) 类似，处理`nums[mid] == nums[right]`的情况即可，移动搜索边界`right--`

## Solution

Template #3

```java
class Solution {
    public int findMin(int[] nums) {
        if (nums == null || nums.length == 0) {
            return 0;
        }
        int left = 0, right = nums.length - 1;
        while (left + 1 < right) {
            int mid = left + (right - left) / 2;
            if (nums[mid] > nums[right]) {
                left = mid;
            } else if (nums[mid] < nums[right]) {
                right = mid;
            } else {
                right--;
            }
        }
        return Math.min(nums[left], nums[right]);
    }
}
```
