Find Minimum in Rotated Sorted Array II
Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand.
(i.e., [0,1,2,4,5,6,7]
might become [4,5,6,7,0,1,2]
).
Find the minimum element.
The array may contain duplicates.
Example 1:
Input:
[1,3,5]
Output:
1
Example 2:
Input:
[2,2,2,0,1]
Output:
0
Note:
This is a follow up problem to Find Minimum in Rotated Sorted Array.
Would allow duplicates affect the run-time complexity? How and why?
Analysis
作为Find Minimum in Rotated Sorted Array 的follow-up,差别在于是否有重复。跟Search in Rotated Sorted Array II 类似,处理nums[mid] == nums[right]
的情况即可,移动搜索边界right--
Solution
Template #3
class Solution {
public int findMin(int[] nums) {
if (nums == null || nums.length == 0) {
return 0;
}
int left = 0, right = nums.length - 1;
while (left + 1 < right) {
int mid = left + (right - left) / 2;
if (nums[mid] > nums[right]) {
left = mid;
} else if (nums[mid] < nums[right]) {
right = mid;
} else {
right--;
}
}
return Math.min(nums[left], nums[right]);
}
}
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