Evaluate Division

Weighted Directed Graph -> Find Path Weight

Medium

Equations are given in the format A / B = k, where A and B are variables represented as strings, and k is a real number (floating point number). Given some queries, return the answers. If the answer does not exist, return -1.0.

Example:

Given 
    a / b = 2.0, b / c = 3.0. 
queries are: 
    a / c = ?, b / a = ?, a / e = ?, a / a = ?, x / x = ? . 
return 
    [6.0, 0.5, -1.0, 1.0, -1.0 ].

The input is: vector<pair<string, string>> equations, vector<double>& values, vector<pair<string, string>> queries , where equations.size() == values.size(), and the values are positive. This represents the equations. Return vector<double>.

According to the example above:

equations = [ ["a", "b"], ["b", "c"] ],

values = [2.0, 3.0],

queries = [ ["a", "c"], ["b", "a"], ["a", "e"], ["a", "a"], ["x", "x"] ]. 

The input is always valid. You may assume that evaluating the queries 
    will result in no division by zero and there is no contradiction.

Solution & Analysis

把问题转化为图 Weighted Directed Graph,然后因为不同的路径到达目标path value应该是一样的,因此只需要用DFS找到一个路径即可返回。

建Adjacency List的时候,因为这是带权重的有向图,要顺便添加反向的edge,也就是1.0/value。

Version 2 - DFS

Version 1 - DFS (2 ms, faster than 64.65%)

Reference

https://leetcode.com/problems/evaluate-division/discuss/171649/1ms-DFS-with-Explanations

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