Given a non-empty, singly linked list with head nodehead, return a middle node of linked list.
If there are two middle nodes, return the second middle node.
Example 1:
Input:
[1,2,3,4,5]
Output:
Node 3 from this list (Serialization:
[3,4,5]
)
The returned node has value 3. (The judge's serialization of this node is [3,4,5]).
Note that we returned a ListNode object ans, such that:
ans.val = 3, ans.next.val = 4, ans.next.next.val = 5, and ans.next.next.next = NULL.
Example 2:
Input:
[1,2,3,4,5,6]
Output:
Node 4 from this list (Serialization:
[4,5,6]
)
Since the list has two middle nodes with values 3 and 4, we return the second one.
Note:
The number of nodes in the given list will be between 1 and 100.
Solution
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */classSolution {publicListNodemiddleNode(ListNode head) {ListNode slow = head;ListNode fast = head;while (fast !=null&&fast.next!=null) { slow =slow.next; fast =fast.next.next; }return slow; }}