# Flatten 2D Vector

Design and implement an iterator to flatten a 2d vector. It should support the following operations:`next`and`hasNext`.

**Example:**

```
Vector2D iterator = new Vector2D([[1,2],[3],[4]]);

iterator.next(); // return 1
iterator.next(); // return 2
iterator.next(); // return 3
iterator.hasNext(); // return true
iterator.hasNext(); // return true
iterator.next(); // return 4
iterator.hasNext(); // return false
```

**Notes:**

1. Please remember to **RESET** your class variables declared in Vector2D, as static/class variables are **persisted across multiple test cases** . Please see [here](https://leetcode.com/faq/) for more details.
2. You may assume that `next()`call will always be valid, that is, there will be at least a next element in the 2d vector when

   `next()` is called.

**Follow up:**

As an added challenge, try to code it using only [iterators in C++](http://www.cplusplus.com/reference/iterator/iterator/) or [iterators in Java](http://docs.oracle.com/javase/7/docs/api/java/util/Iterator.html).

## Solution

Using Index i, j - (**72 ms, 11.78%)**

```java
class Vector2D {

    private int i, j;
    private int[][] v;
    public Vector2D(int[][] v) {
        i = 0;
        j = 0;
        this.v = v;
    }

    public int next() {
        int n = 0;
        if (i < v.length && j >= v[i].length) {
            while (i < v.length) {
                i++;
                if (j < v[i].length) {
                    break;
                }
            }
        }
        n = v[i][j];
        if (j == v[i].length - 1) {
            j = 0;
            i++;
        } else {
            j++;
        }
        return n;
    }

    public boolean hasNext() {
        int ti = i;
        int tj = j;
        if (ti < v.length && tj < v[ti].length) {
            return true;
        } else if (ti < v.length) {
            while (ti < v.length) {
                if (tj < v[ti].length) {
                    return true;
                }
                ti++;
            }
        }
        return false;
    }
}

/**
 * Your Vector2D object will be instantiated and called as such:
 * Vector2D obj = new Vector2D(v);
 * int param_1 = obj.next();
 * boolean param_2 = obj.hasNext();
 */
```

Iterator

```java
public class Vector2D {

    private Iterator<List<Integer>> i;
    private Iterator<Integer> j;

    public Vector2D(List<List<Integer>> vec2d) {
        i = vec2d.iterator();
    }

    public int next() {
        hasNext();
        return j.next();
    }

    public boolean hasNext() {
        while ((j == null || !j.hasNext()) && i.hasNext())
            j = i.next().iterator();
        return j != null && j.hasNext();
    }
}
```

Another

```java
public class Vector2D {
    int indexList, indexEle;
    List<List<Integer>> vec; 

    public Vector2D(List<List<Integer>> vec2d) {
        indexList = 0;
        indexEle = 0;
        vec = vec2d;
    }

    public int next() {
        return vec.get(indexList).get(indexEle++);
    }

    public boolean hasNext() {
        while(indexList < vec.size()){
            if(indexEle < vec.get(indexList).size())
                return true;
            else{
                indexList++;
                indexEle = 0;
            }
        }
        return false;
    }
}
```


---

# Agent Instructions: Querying This Documentation

If you need additional information that is not directly available in this page, you can query the documentation dynamically by asking a question.

Perform an HTTP GET request on the current page URL with the `ask` query parameter:

```
GET https://aaronice.gitbook.io/lintcode/data_structure/flatten-2d-vector.md?ask=<question>
```

The question should be specific, self-contained, and written in natural language.
The response will contain a direct answer to the question and relevant excerpts and sources from the documentation.

Use this mechanism when the answer is not explicitly present in the current page, you need clarification or additional context, or you want to retrieve related documentation sections.
