Reverse Linked List
Reverse a singly linked list.
Example:
Input: 1->2->3->4->5->NULL
Output: 5->4->3->2->1->NULL
Solution
iterative
public ListNode reverseList(ListNode head) {
ListNode prev = null;
while (head != null) {
ListNode next = head.next;
head.next = prev;
prev = head;
head = next;
}
return prev;
}
public ListNode reverseList(ListNode head) {
ListNode prev = null;
ListNode curr = head;
while (curr != null) {
ListNode nextTemp = curr.next;
curr.next = prev;
prev = curr;
curr = nextTemp;
}
return prev;
}
recursive
public ListNode reverseList(ListNode head) {
if (head == null || head.next == null) return head;
ListNode p = reverseList(head.next);
head.next.next = head;
head.next = null;
return p;
}
ListNode newHead;
public ListNode reverseList(ListNode head) {
if (head == null) {
return null;
}
return reverseUtil(head, null);
}
ListNode reverseUtil(ListNode curr, ListNode prev) {
/* If last node mark it head*/
if (curr.next == null) {
newHead = curr;
/* Update next to prev node */
curr.next = prev;
return newHead;
}
/* Save curr->next node for recursive call */
ListNode next = curr.next;
/* and update next ..*/
curr.next = prev;
reverseUtil(next, curr);
return newHead;
}
Reference Code
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode reverseList(ListNode head) {
if (head == null) {
return head;
}
ListNode currentHead = head;
while (head.next != null) {
ListNode p = head.next;
head.next = p.next;
p.next = currentHead;
currentHead = p;
}
return currentHead;
}
}
Using Dummy Node Version
class Solution {
public ListNode reverseList(ListNode head) {
if (head == null) {
return null;
}
ListNode dummy = new ListNode(0);
ListNode p = head;
dummy.next = head;
while (p.next != null) {
ListNode q = p.next;
p.next = q.next;
q.next = dummy.next;
dummy.next = q;
}
return dummy.next;
}
}
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